4x^2+x^2=1125

Solution for 4x^2+x^2=1125 equation:

4x^2+x^2=1125

We move all terms to the left:

4x^2+x^2-(1125)=0

We add all the numbers together, and all the variables

5x^2-1125=0

a = 5; b = 0; c = -1125;
Δ = b2-4ac
Δ = 02-4·5·(-1125)
Δ = 22500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{22500}=150$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-150}{2*5}=\frac{-150}{10}
=-15
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+150}{2*5}=\frac{150}{10}
=15
$